**Physics Practicals Class 12**

# Convex Lens β Focal Length

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### About Simulation

- This simulation will give an entire idea about image formation by convex lens in focal length of convex lens experiment.
- You will get the knowledge of determining focal length, the basics of convex lens and lens formula.
- You will learn and apply the lens formula to find the focal length of the convex lens.
- This interaction provides a very immersive environment and gives you a real-lab-like experience while conducting or performing experiments.
- All the experiment steps and procedures, like measuring the image and object distance, removing parallax error, calculating index correction, etc., and many more are highly interactive and have been simulated in a very similar manner as you do in a physics lab.

- This will help learners to better prepare for various competitive exams such as IIT-JEE (JEE Main & Advanced), NEET, and Olympiads.

### Simulation Details

Description

For an object placed at a distance π’ from the optical centre of a thin convex lens of focal length π, a real and inverted image is formed on the other side of the lens at a distance π£ from the optical centre. $$ \frac{1}{f}=\frac{1}{v}-\frac{1}{u}$$

According to sign conventions, π’ = βve, π£ = +ve

$$\Rightarrow f=\frac{u v}{u+v}$$

Here, figure (a) shows image formation by a convex lens when π’ = 2π and figure (b) shows

the image formation by a convex lens when 2π > π’ > π.

The graph of ^{1} –_{π£} versus ^{1} –_{π’} is a straight line with a negative slope.

$$\text{ If } \frac{1}{v}=0 \text{ or } \frac{1}{u}=0, \text{ then } \frac{1}{u}=\frac{1}{f} \text{ or } \frac{1}{v}=\frac{1}{f}$$

The graph of π’ versus π£ is a hyperbola. When π’ = π£, then π’ = π£ = 2π.

### Requirements for this Science Experiment

β¦ Optical Bench β¦ Convex Lens β¦ Optical Needles β¦ Uprights β¦ Lens Holder

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