Physics Practicals Class 12
Potentiometer – Internal Resistance of a Cell
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About Simulation
- In this simulation, you will learn about the potentiometer apparatus and its components in a virtual lab.
- You will learn about the balancing principle of the potentiometer and determine the internal resistance of a cell.
- You will repair the potentiometer of the car music player and get more information about the potentiometer.
- All the potentiometer experiment steps and procedures, like connecting wires, observing galvanometer deflections, measuring the balancing length, noting down the readings, etc., are highly interactive and have been simulated in a very similar manner as you do in a physics lab.
- This interaction provides a very immersive virtual reality environment and gives you a real-lab-like experience while conducting or performing experiments.
- It is one of the important class 12 physics practicals that you can learn in our virtual lab.
Simulation Details




Description
Potentiometer is a device used to compare the EMF (electromotive force) of two cells, to measure the internal resistance of a cell, and the potential difference across a resistor. It consists of a long wire (10 m) having a uniform cross-sectional area. The wires are stretched parallel to each other on a wooden board.
The wires are joined in series by using thick copper strips. A meter scale is also attached to the wooden board. The potentiometer works on the potentiometer principle, that is when a constant current flows through a wire of uniform cross-sectional area, the potential difference between its two points is directly proportional to the length of the wire between the two points.
If a cell of EMF πΈ and internal resistance π, is connected to an external resistance π , then the circuit has the total resistance (π + π). The current πΌ in the circuit is given by, $$I=\frac{E}{R+r}$$
$$E=I R+I r$$
We know that π = πΌπ . So, $$E=V+I r \Rightarrow V=E-I r$$
Using a potentiometer, we can adjust the rheostat to obtain the balancing lengths π1 and π2 of the potentiometer for open and closed circuits, respectively.
Then, πΈ = ππ1 and π = ππ2; where π is the potential gradient along the wire.
Now, we can modify the equation for getting the internal resistance of the given cell, by using the above relations as;$$r=R \frac{l_1-l_2}{l_2}$$
Requirements for this Science Experiment
β¦ Potentiometer β¦ LeclanchΓ© Cell β¦ Resistance Box β¦ Jockey β¦ Galvanometer β¦ Ammeter β¦ Galvanometer β¦ Plug key
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